(2/32)(3/32)(4/32)(5/32)(6/32)(7/32)(8/32)(9/32... May 2026

We can rewrite the product of these 31 fractions as a single expression using factorials:

∏n=232n32≈2.14×10-13product from n equals 2 to 32 of n over 32 end-fraction is approximately equal to 2.14 cross 10 to the negative 13 power 1. Identify product sequence (2/32)(3/32)(4/32)(5/32)(6/32)(7/32)(8/32)(9/32...

The following graph shows how the cumulative product decreases as more terms are added to the sequence. The product of the sequence is exactly We can rewrite the product of these 31

The given expression is a product of fractions where the numerator increases by 1 for each term and the denominator remains constant at . The general term is . Based on the pattern, the sequence likely starts at and ends at (the point where the fraction equals 1). 2. Formulate the equation The general term is

P=2×3×4×…×323231cap P equals the fraction with numerator 2 cross 3 cross 4 cross … cross 32 and denominator 32 to the 31st power end-fraction