(2/56)(3/56)(4/56)(5/56)(6/56)(7/56)(8/56)(9/56... -

until the final term, causing the total product to decrease exponentially. ✅ Final Result The total product for the sequence up to is approximately

The sequence provided follows the general form of a product of fractions where the numerator increases by in each term while the denominator remains constant at . The expression is written as: (2/56)(3/56)(4/56)(5/56)(6/56)(7/56)(8/56)(9/56...

The following graph illustrates how the cumulative product shrinks as more terms are added. Each subsequent term n56n over 56 end-fraction is less than until the final term, causing the total product

In most mathematical contexts for this specific pattern, the sequence concludes when the numerator reaches the denominator ( 2. Simplify using factorials until the final term